Question

Four students have a mean weight of 26Kg. When they are joined by a fifth student their mean weight decreased to 24Kg . What is the weight of the fifth student ?

Answer 1

Answer:

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Answer 2

Answer:

16 kgs.

Step-by-step explanation:

⇒ $\frac{a+b+c+d}{4}$ = $26 kg$

⇒ $a+b+c+d= 26*4$

⇒ $a+b+c+d = 104$

When the 5th student is added:

⇒ $\frac{a+b+c+d+e}{5} = 24 kg$

⇒ $a+b+c+d+e$ = $120 kg$

Then we will subtract:

120 kgs - 104 kgs = 16 kgs

Answer: Weight of the 5th student is 16 kgs.