Question

Four students were asked by their teacher to arrange the set-ups I-IV as given below and identify the gas evolved in each case, if any.

Answer 1

Option 3 is correct for the above question

Answer 2

Answer:

I- Carbon dioxide

II- Hydrogen gas

III- Hydrogen gas

IV- No gas

Therefore, the student C reported the correct observations and inferences.

Explanation:

(1.) In the first test tube, sodium carbonate mixed with dilute HCl :-

When dilute hydrochloric acid (HCl) reacts with sodium carbonate then the products sodium chloride, carbon dioxide, and water are formed.

HCl(aq)  +  Na₂CO₃ (s)  $\longrightarrow$  NaCl (aq)    +  CO₂ (g)   +  H₂O (l)

(2.) In the second test tube, Zinc mixed with NaOH :-

Zinc reacts with the sodium hydroxide and gives sodium zincate and hydrogen gas.

Zn (s)  +   2NaOH   $\longrightarrow$  Na₂ZnO₂    +  H₂ (g)

(3.) In the second test tube, Zinc mixed with dil. HCl :-

Acid reacts with metal to produce the metal salt and hydrogen gas. When dilute hydrochloric acid (HCl) reacts with zinc, it produces zinc chloride salt and hydrogen gas.

Zn (s)  +  dil. HCl    $\longrightarrow$  ZnCl₂   +  H₂ (g)

(4.)  In the second test tube, Sodium carbonate mixed with sodium hydroxide :-

Both, Sodium carbonate and sodium hydroxide are bases. Bases do not react each other. So , there is no reaction in the 4th test tube and no evolution of gas.

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