Question

Four times a number and 3 timrs another number added together make 43 two times the second number subtracted from 3 times the first gives 11 what are the numbers

Answer 1

Frist number =7 and second number is 5

let us assume that

Frist number br x and second number as y

according to given data

"four times of a number and 3 times of another number will sum up 43 means"

4x+3y=43 ............ equation 1

and from second condition

we get as

2 times of second number was subtract from 3 times of Frist number so

it gives

3x-2y=11 ........ equation 2

now solve equation 1 and 2

by any favourable number

I am going to do elimination method

so

the equations made are

4x+3y=43

3x-2y=11

multiple 3 with equation 1 and subtract 4(times of equation 2)

that gives

12x+9y=129

12x -8y =44

-. +. = -

that gives

17y=85

y=5

now

put value of y in equation 2

so

3x-2(5)=11

3x=11+10

3x=21

x=7

therefore

the values are

7 and 5