Question

Four times a number and three times another number added together
make 43. Two times the second number, subtracted from three times the
first gives 11. What are the numbers?
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Answer 1

Answer:numbers are 7 and 5

Step-by-step explanation:

Let the two numbers be x and y.

By question,

4x+3y=43........(1),and

3x-2y=11............(2)

Multiplying both sides of (1) by 2 we get

8x+6y=86

Multiplying both sides of (2) by 3 we get

9x-6y=33

Now adding above two equations we get

17x=119

Therefore x=7

Putting this value of x in any of the above equations we get

3×7-2y=11

Or,21-11=2y

Or,10=2y

Therefore y =5

Answer 2

Answer:

x = 7 y = 5

Step-by-step explanation:

first no = 7 , second no = 5