four times a number and three times of another number added together make 43.two times the second number subtracted from three times the first gives 11.what are the number?
Answers
Answer:
The first number is 7 and the second number is 5
Step-by-step explanation:
Let the first number be x and the second number be y
1st condition: 4 times a number and 3 times another number added together is 43
∴ 4x + 3y = 43 ---- (1)
2nd condition: 2 times the second number subtracted from 3 times the first number is 11
∴ 3x - 2y = 11 ---- (2)
Multiplying eqn (1) by 2
2( 4x + 3y = 43)
=> 8x + 6y = 86 ---- (3)
Multiplying eqn (2) by 3
3( 3x - 2y = 11)
=> 9x - 6y = 33 ---- (4)
Adding eqns (3) and (4)
8x + 6y = 86
9x - 6y = 33
----------------
17x = 119
x= 119/17 = 7
∴ x = 7
Substituting x = 7 in eqn (1)
4x + 3y = 43
4(7) + 3y = 43
28 + 3y = 43
3y = 43 - 28
3y = 15
y = 15/3 = 5
∴ y = 5
∴ The first number is 7 and the second number is 5
Step-by-step explanation:
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