Question

Four times a number substrated from the square of the number gives 96 what will the number​

Answer 1

Let the no. be x

${x}^{2} - 4x = 96 \\ {x}^{2} - 4x - 96 = 0$

(x-12)(x+8)= 0

x can be 12 or -8

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Answer 2

Answer:

Step-by-step explanation:

Let d no. be x

Given,

x^2-4x=96

x^2-4x-96=0

x^2-12x+8x-96=0

x(x-12)+8(x-12)=0

(x-12)(x+8)=0

=>x=12,-8

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