Question

Four times geeta age plus five times seeta age is 56. Seven times geeta age minus twice seeta age is 12. Find their ages.

Answer 1

Answer:

Let geeta's age be x

let seeta's age be y

4x+5y=56-(1)

7x-2y=12-(2)

multiply eq.1 and eq2 with 2 and 5 respectively and on solving ,we get

8x+10y=12

35x-10y=60

43x=172

x=172/43

x=4

so,geeta's age =4

put x=4 in eq.1 ,we get

4(4)+5y=56

16+5y=56

5y=56-16

5y=40

y=40/5

y=8

so,seeta's age =8