Math, asked by pavanchunduri109, 8 months ago

four times the age of a mother is equal to nine times the age of her daughter. after nine years the mother's age will be twice her daughter's age. what is the present age of the daughter​

Answers

Answered by deepakloni
64

Answer:

four times the age of a mother is equal to nine times the age of her daughter. after nine years the mother's age will be twice her daughter's age. what is the present age of the daughter

Answered by priyadarshinibhowal2
0

The present age of the daughter​ is 36 years.

  • An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation with one variable has the conventional form Ax + B = 0. In this case, the variables x and A are variables, while B is a constant. A linear equation with two variables has the conventional form Ax + By = C.
  • Each term in a linear equation has an exponent of 1, and when this algebraic equation is graphed, it always produces a straight line. It is called a "linear equation" for this reason.

Here, according to the given information, we are given that,

Four times the age of a mother is equal to nine times the age of her daughter.

Let the present age of the daughter​ be x.

Let the present age of the mother be y.

Then, we have, 4y = 9x.\\

Also, after 9 years, we will have,

(y+9) = 2(x+9)

Or, y=2x +9.

Now, by putting the value of x in this equation, we will get,

y = 2(\frac{4y}{9} )+9

Or, y - \frac{8y}{9} =9

Or, y = 81.

Then, x = \frac{4.81}{9} =36.

Hence, the present age of the daughter​ is 36 years.

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