four times the area of curved surface of a cylinder is equal to 6 times the sum of the area of its two bases if its size is 12 find its curved surface area.
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Solution:-
Curved Surface Area cylinder = 2πrh
Area of the base = πr²
Sum area of the base= πr²+πr²= 2πr²sq.cm
A.T.Q
=> 4 (2πrh) = 6 × 2πr²
=> 8πrh = 12πr²
=> 2h = 3r
=> 2 × 12 = 3r
r = 8cm.
Curved Surface Area cylinder = 2πrh
=> 2 × 22/7 × 8 × 12
=> 4224/7
=> 603.42 sq.cm
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Curved surface area of a cylinder = 2πrh
Area of the base = πr²
Area of both base = 2πr²
GIVEN THAT
4×2πrh = 6×2πr²
4 x 2πr x 12 = 6 x 2 x πr x r
r = 8
Curved Surface area = 2πrh
= 2×π×8×12
= 192π cm²
HOPE this helps you ☺️
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