Math, asked by Anonymous, 1 month ago

four times the area of curved surface of a cylinder is equal to 6 times the sum of the area of its two bases if its size is 12 find its curved surface area.​,


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Answers

Answered by FlawlessHeart
3

Solution:-

Curved Surface Area cylinder = 2πrh

Area of the base = πr²

Sum area of the base= πr²+πr²= 2πr²sq.cm

A.T.Q

=> 4 (2πrh) = 6 × 2πr²

=> 8πrh = 12πr²

=> 2h = 3r

=> 2 × 12 = 3r

r = 8cm.

Curved Surface Area cylinder = 2πrh

=> 2 × 22/7 × 8 × 12

=> 4224/7

=> 603.42 sq.cm

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Answered by Anonymous
36

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Curved surface area of a cylinder = 2πrh

Area of the base = πr2

∴ Area of both base = 2πr2

According to question,

4×2πrh = 6×2πr2

⇒ 4 x 2πr x 12 = 6 x 2 x πr x r

⇒r = 8

∴ Volume of a cylinder = πr2h

= π x 8 x 8 x 12

=768πcm3

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