Question

Four times the cube of a positive number decreased by seven times the square of the same number is equal to 65 times the number. Find the number.

Answer 1

Answer:

let the no. = x

Given =

7x²- 4x³ = 65x

7x²- 4x³ -65x = 0

x(7x -4x²-65) = 0

x = 0/7x-4x²-65

x= 0

So the number = 0

Hope this helps

Answer 2

Step-by-step explanation:

Four times the cube of a positive number decreased by seven times the square of the same number is equal to 65 times the number