Question

Four times the first of three consecutive odd integers is 6 more than twice the third. The third integer is

Answer 1

let the consecutive odd integers be 2x+1, 2x+3, 2x+5

4(2x+1)=6+2(2x+5)
8x+4=6+4x+10
4x=12
x=3

therefore, the third integer is-
2x+5=2(3)+5
       =6+5
       =11.....ans.

Answer 2

let the 3 consecutive odd integers be
X, X+2, X+4
it is given that,

4×X=6+{2×(X+4)}
4X=6+2X+8
4X=114+2X
2X=14
X=7

third integer is X+2=7+2=9

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