Question

Four variates are 2 4 6 8.The frequences of the first three variates are 3 2 1 respectively.If the mean of the variates is 4 then find the frequence of the fourth variate

Answer 1

MEAN =[(2×3)+(4×2)+(6×1)+(8×m)]÷4 [let "m" be 4th frequency ]

4 =(6+8+6+8m) ÷4

4×4 =6+8+6+8m

16=20+8m

8m=-4

M=-1/2

So this mean is invalid and it is not possible to findo out 4th frequency