four year ago age of a person was 9 times that of his son.four year later the age of the person will be four time the age of his son at that time find the present age of the person and his son
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Let the present ages of the person and his son be x years and y years respectively.
Given, x−4=4(y−4)
⇒x−4=4y−16
⇒x−4y=−12 ....(1)
And also given, x+6=3(y+6)−10
⇒x+6=3y+8
⇒x−3y=2 ....(2)
By solving the equations (1) and (2), we get
x=44 and y=14
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