Four year ago arka was twice as old as sania. and now sania will be 3/4 of arka age.how old arka now
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Let the age of Arka be x
and sania be y
Before four years ,
Arka' s age :- x - 4
Sania's age :- y - 4
x - 4 = 2 ( y - 4 )
x - 4 = 2y - 8
x - 2y - 4 + 8 = 0
x - 2y + 4 = 0 .... ( i )
Now ,
y = 3/4 × x
y = 3x /4 .... ( ii )
Putting value of y from ( ii ) in ( i )
x - 2y + 4 = 0
x - 2 × 3x/4 + 4 = 0
x - 3x /2 + 4 = 0
( 2x - 3x + 8 ) /2 = 0
- x + 8 = 0
x = 8
Putting in ( ii )
y = 3 × 8 /4
y = 6
Arka' s age is 8 years
and Sania's age is 6 years.
and sania be y
Before four years ,
Arka' s age :- x - 4
Sania's age :- y - 4
x - 4 = 2 ( y - 4 )
x - 4 = 2y - 8
x - 2y - 4 + 8 = 0
x - 2y + 4 = 0 .... ( i )
Now ,
y = 3/4 × x
y = 3x /4 .... ( ii )
Putting value of y from ( ii ) in ( i )
x - 2y + 4 = 0
x - 2 × 3x/4 + 4 = 0
x - 3x /2 + 4 = 0
( 2x - 3x + 8 ) /2 = 0
- x + 8 = 0
x = 8
Putting in ( ii )
y = 3 × 8 /4
y = 6
Arka' s age is 8 years
and Sania's age is 6 years.
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