four year ago George was four times older than his daughter.After four years,George will be 2 years more than two times the age of his dayghter.Find the present age of George and his daughter
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let the age of George daughter 4years ago be x
then age George= 4x
there presen age= x+4 and 4x+4
after 4 years
age of daughter= x+4+4= x+8
age of georgr= 4x+8
a/q
4x+8= 2(x+8) +2
4x+8= 2x+16+2
4x+8=2x+18
4x-2x= 18-8
2x=10
x= 5 years
so present age of daughter = x+4= 9 years
age of george= 4x+4= 24 ans
then age George= 4x
there presen age= x+4 and 4x+4
after 4 years
age of daughter= x+4+4= x+8
age of georgr= 4x+8
a/q
4x+8= 2(x+8) +2
4x+8= 2x+16+2
4x+8=2x+18
4x-2x= 18-8
2x=10
x= 5 years
so present age of daughter = x+4= 9 years
age of george= 4x+4= 24 ans
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