Math, asked by sanketmhaske1734, 1 year ago

Four year ago the age of a and b in the ratio of 2:3 after 4 year its age will ne 5:7 find the present age

Answers

Answered by Anonymous
3

Let their ages before 4 years be a,b respectively.

4 years ago,

a / b = 2/3

a=(2/3)b

4 years later, means a+8,b+8

a+8 / b+8 = 5 / 7

by cross multiplying.

7a + 56 = 5b +40

solving above two equations for a and b, we get

a= 32

b= 48

so their present ages are

a+4 = 36

b+4 = 52

hence

A's present age is 36 yrs

B's present age is 52 yrs

Hope it helped you.

Please let me know if any further doubt.

Cheers !!!

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