Question

Four years ago A age was 3 times B age. After 8 years A age will be twice B. Then the sum of their present ages is​

Answer 1

Given :

Given that, four years ago, A was 3 times B age and after 8 years, A will be twice B.

To find :

We have to find the sum of their present ages.

Solution :

Let the ages of A and B be x and y respectively.

From the question, four years ago :

• A - 4 = 3 (B - 4)
• x - 4 = 3y - 12 _____( eq . 1 )

Also, after 8 years :

• A + 8 = 2 (B + 8)
• x + 8 = 2y + 16 _______( eq . 2 )

Now, solving the equations 1 and 2 :

• x = 3y - 12 + 4 ( From eq . 1 )
• x = 3y - 8 ________( eq . 3 )

Substituting equation 3 in equation 2 :

• x + 8 = 2y + 16
• 3y - 8 + 8 = 2y + 16
• 3y - 2y = 16
• y = 16 years

Substituting y = 16 in equation 3 :

• x = 3y - 8
• x = 3 (16) - 8
• x = 48 - 8
• x = 40 years

Finding the sum of their ages :

• x + y
• 16 + 40
• 56 years

_________________________

Therefore, the sum of the present ages of A and B is 56 years.

Answer 2

Answer:

a+b =56 years hence it is confirmed