Question

four years ago a father was 6 times as old as his son ten years later the father was two and half times as old as his son determine the present age of father and his son​

Answer 1

Answer:

Let son age 4years ago be x and fathers age be 6x

10 years later son age is (x+14)and father age be (6x+14).

6x+14=5/2(x+14)

6x+14=5/2x+35

6x–5/2x=35–14

7/2x=21

x=21÷7/2

=6

son age =6+4=10

father age =40