Question

Four years ago a father was nine times as old as his son, and 8 years hence the father 's age will be three times the son's age. Find their present ages​

Answer 1

Step-by-step explanation:

its your answer ❤️⚔️⚔️

Answer 2

Solution :

• Let the present age of the father be m years and present age of son be n years.

◖ FOUR YEAR'S AGO :

⌬ The age of father was (m - 4) years

⌬ And the age of son was (n - 4) years

᠂ According to the Question Now :

• Four years ago a father was nine times as old as his son :

↠(m - 4) = 9(n - 4)

↠m - 4 = 9n - 36

↠m = 9n - 36 + 4 ...(eqⁿ i )

◖ EIGHT YEAR'S HENCE :

• The age of father will be (m + 8) years
• The age of son will be (n + 8) years

᠂ According to the Question Now :

• 8 years hence the father's age will be three times the son's age :

⇏(m + 8) = 3(n + 8)

⇏m + 8 = 3n + 24

Substituting the value of m from eqⁿ (i) we get :

⇏9n - 36 + 4 + 8 = 3n + 24

⇏9n - 24 = 3n + 24

⇏9n - 3n = 24 + 24

⇏6n = 48

⇏n = 48 ÷ 6

⇏n = 8 years

Now, substitute the value of n = 8 in eqⁿ :

⇏m = 9(8) - 36 + 4

⇏m = 72 - 36 + 4

⇏m = 72 - 32

⇏m = 40 years

◖ PRESENT AGE OF FATHER AND SON :

• Present age of father = m = 40 years
• Present age of son = n = 8 years