Question

Four years ago a man was 6 times as old as his son. After 16 years he will be twice as old as his son. What is the present age of man and his son?

Answer 1

Four years ago

the age of son is x- 4

And , the age of man = 6x-4

A/q - 2( x-4+16) = 6x -4+16

or, 2x - 8 + 32 = 6x-4+16

or, 2x + 24 = 6x + 12

or , 24 - 12 = 6x - 2x

or, 12 = 4x

or, 12/4 = x

or, 3 = x

The age of son = 3 yrs.

The age of man = 22 yrs.

Answer 2

Answer:

34,9

Step-by-step explanation:

Let's assume the current age of father and his son are x and

respectively.

So, 4 years back age of father and his son would be:

x-4 and y-4 respectively

Now, according to the question,

Age of father = 6 * (age of son)

Which means x-4 = 6(y-4);

x-4=6y-24

x= 6y-20 (equation 1)

Similarly after 16 years, age will be

x+16 and y+16

As per the question,

(x+16) = 2(y+16)

x+16 = 2y+32

x=2y+16(equation 2)

Using equation 1 and 2

6y-20=2y+16

4y=36

y=36/4=9

Using first x=6y-20

x=6(9)-20

=54–20

=34

Hence the ages will be 34 and 9 years old.

Hope it helped!