Question

Four years ago father was eight times as old as his son was. Six years he will be three times as old as his son will be. Then their present age is
options are
Father = 32 years Son= 4 years
Father = 36 years Son= 8 years
Father= 28 years Son= 7 years
Father = 36 years Son= 9 years

Answer 1

Answer:

Let the present age of father's be x years and present age of son's be y years.

According to the problem

x=6y

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y

x+4=4(y+4)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 year

Answer 2

Answer:

Father = 32 years Son= 4 years is the correct answer