Question

Four years ago George was four times older than his daughter. After four years, George will
be 2 years more than two times the age of his daughter. Represent the given condition in
the form of pair of linear equations in two variables Find thepresent age of George and
hisdaughter.

Answer 1

___________________

ＳＯＬＯＵＴＯＮ :-

___________________

Let the present age of George be = x years

and present age of her daughter is = y years

4 years ago,

George age be = x - 4

Daughter age be = y - 4

$x - 4 = 4(y + 4)$

$x - 4 = 4y + 12$

$x = 4y + 12 .......(1)$

After four years,

George age be = x +4

Daughter age be = y+ 4

$x + 4 = 2y(y + 4 + 2)$

$x + 4 = 2y + 8 + 4$

$x + 4 = 2y + 12......(2)$

Substitute the value of x in equation 2

$x + 4 = 2y + 12$

$4y + 4 = 2y + 12$

$4y - 2y = 12 - 4$

$2y = 8$

➡$y = 4$

Value of y put in equation 1

$x = 4y + 12$

$x = 4.4 + 12$

$x = 16 + 12$

➡x= 28

So, the present age of George is 28 years and her daughter age is 4 years.

___________________________