Question

Four years ago Madhav was three times as old as his daughter. Six years from now
the father will be twice as old as his daughter. Find their present ages.​

Answer 1

Answer:

madav age =x

daughter age = y

four years ago

x-4 = 3(y-4)

x-4 = 3y-12

x-3y= -8 (1)

6 years from now

x+6 = 2(y+ 6)

x+6 = 2y + 12

x-2y = 6 (2)

subtracting 1 and 2

x-3y - x+2y= -8 -6

-y = -14

y = 14

so x= 34

Step-by-step explanation:

HOPE U UNDERSTAND THE QUESTION