Question

Four years ago, Maria's age was twice Tatiana's. In 8 years Tatiana's age will be 5
8 of Four years ago, Maria's age was twice Tatiana's. In 8 years Tatiana's age will be 5
8 age of Maria How old are Maria and Tatiana now? helpme plissss

Answer 1

Answer:

correction => 5/8 instead of 5 8

age of Maria= 40 years

age of Tatiana = 22 years

Step-by-step explanation:

let the present age of Maria be X and Tatiana be Y years old

=> X-4 = 2(Y-4)

=> X-2Y = - 4...................(1)

also

Y+8 = (5/8)(X+8)

8(Y+8) = 5(X+8)

=> 5X-8Y = 24............(2)

from(1) and (2)

X= 40 years

putting in (1)

-2Y = -44

=> Y= 22 years

therefore

present age of Maria = 40 years

present age of Tatiana = 22 years

hope this helps you

Answer 2

Given :  Four years ago, Maria's age was twice Tatiana's  In 8 years Tatiana's age will be 5/8 age of Maria

To Find : Present ages of  Maria  & Tatiana

Solution:

Let say  now  Maria Age  = M  Years

&  Tatiana age  =  T  Years

Four years ago, Maria's age was twice Tatiana's

=> M - 4  = 2 (T - 4)

=> M  = 2 T  - 4

In 8 years Tatiana's age will be 5/8 age of Maria

=> T + 8  =  (5/8) ( M  +  8)

=> 8(T + 8)  = 5(M + 8)

using M = 2 T  - 4

=> 8(T + 8)  = 5( 2 T  - 4  + 8)

=> 8T + 64  = 10T + 20

=>  2T = 44

=> T = 22

M = 2T - 4  =  40

Maria Age = 40  Years

Tatiana's Age  = 22  Years

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