Question

four years ago marina was three times old as her daughter. six years from now the mother will be twice as old as her daughter. find their present ages

Answer 1

Maria is about 34 year old
daughter is 14 year old.
take a look at picture.

Answer 2

Heya !!!


Let the present age of mother and daughter be X and Y year's.


Before four years age of mother = (X-4) years.


Before four years age of daughter = (Y-4) years.


According to question,


(X-4) = 3(Y-4)

X - 4 = 3Y - 12


X - 3Y = -12 + 4


X - 3Y = -8 ---------(1)


After 6 years age of mother = (X+6) years.


After 6 years age of daughter = (Y+6) years.


According to question,


(X+6) = 2(Y+6)


X + 6 = 2Y + 12


X - 2Y = 12-6


X - 2Y = 6 ---------(2)



From equation (1) we get,

X - 3Y = -8


X = -8 + 3Y -----------(3)


Putting the value of X in equation (2)


X - 2Y = 6


-8 + 3Y - 2Y = 6


Y = 6+8

Y = 14 years


Putting the value of Y in equation (3)


X = -8 + 3Y = -8 + 3 × 14 = -8 + 42


X = 34 years



Age of mother = X = 34 years


And,


Age of daughter = Y = 14 years.




HOPE IT WILL HELP YOU...... :-)