Four years ago, Mr. dela Cruz was 5 times as old as his son. How old is his son now if his age is 1/3
of his father's present age?
Answers
Answered by
4
Answer:
Step-by-step explanation:
Let 'x' be age of son.
Let 'y' be age of Mr. Dela Cruz
5(x-4)=y-4
5x-20=y-4
5x-y=-4+20
5x-y=16----------(1)
x=\frac{1}{3} y
3x=y
3x-y=0------------(2)
-y=-3x
y=3x
Substituting y=3x in equation (1)
5x-3x=16
2x=16
x=/frac{16}{2}
x=8
Age of son is 8 years
Answered by
1
Answer:
8
Step-by-step explanation:
(D - 4) = 5 ( S - 4
D = 3S.
3S - 4 = 5S - 20
S = 8
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