Question

Four years ago, priya was twice as old as manish. four years on from now, manish will be 3/4 of priya's age. how old is priya now?

Answer 1

Let Manish's present age be x years

So, the present age of Priya be 2x years

Their ages 4 years from now »

Manish = (x + 4) years

Priya = (2x + 4) years

According to Question,

Manish's age = 3 / 4 of Priya's age

(x + 4) = 3 / 4 × (2x + 4)

⇒ 4(x + 4) = 3(2x + 4)

⇒ 4x + 16 = 6x + 12

⇒ 16 - 12 = 6x - 4x

⇒ 4 = 2x

⇒ 4 / 2 = x

⇒ 2 = x

Required present Ages »

Manish = x = 2 years

Priya = 2x = 2(2) = 4 years

Hence, the present ages of Manish and Priya are 2 years and 4 years respectively.

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Answer 2

Answer: The present age of priya is 4 years.

Explanation:

Given:We have given here,four years ago, Priya was twice as old as Manish. four years on from now, Manish will be 3/4 of Priya's age.

To find:We have find the present age of Priya.

Step 1:Let the present age of Manish is x years.

Step 2:Let the present age of Priya is 2x years.

Step 3:After four years from now Manish age will be (x+4) years.

Step 4: After four years from now Priya age will be (2x+4) years.

Step 5:According to the question,after four years Manish age will be $\frac{3}{4}$ of                       Priya age.

So,

 ⇒                                  $(x+4) = \frac{3}{4}(2x+4)$

 ⇒                                $4(x+4) = 3(2x+4)$

 ⇒                                 $4x+16 = 6x+12$

 ⇒                                 $4x-6x = 12-16$

 ⇒                                       $-2x = -4$

 ⇒                                           $x = \frac{-4}{-2}$

 ⇒                                           $x = \frac{4}{2}$

 ⇒                                           $x = 2$

Step 6:Therefore,the present age of Manish is $x = 2$ years.

Step 7:The present age of Priya is $2x = 2$ × $2$

                                                              $= 4$ years.

Hence, Priya is 4 years old now.

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