Math, asked by safnajaleelpnr87, 3 months ago



Four years ago, Raju’s father’s age was 8 times of Raju’s age. After 6 years, his age will be 3 times Raju’s age. Find their present ages.
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Answers

Answered by sajidalli8114
1

Raju's present age is 8 and that of his father's age is 36 years

Step-by-step explanation:

let the Raju's present age be x and that of his father's age be y

then four years ago Raju's age was (x-4) years and that of his father's age was (y-4) years.

A.T.Q:- (y-4)=8(x-4)

  • y-4=8x-32
  • 8x-y-28=0. —¹

after 6 years,Raju's agree will be x+6 and that if his father will be y+6 year

A.T.Q:- y+6=3(x+6)

  • y+6=3x+18
  • 3x-y+12=0 —²

by the elimination method we get, x=8 & y= 36

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