Math, asked by bangerajyotil, 8 months ago

four years ago ravi was 8 years older than priya. if he is now 3 times as old as she us, find their present age?​

Answers

Answered by VishnuPriya2801
46

Answer:-

Let Ravi's age be x years and Priya's age be y years.

Given:

Ravi is 3 times the age of Priya..

⟹ Ravi's age = 3 * Priya's age

⟹ x = 3y -- equation (1)

And,

Before 4 years, Ravi was 8 years older than Priya.

  • Priya's age before 4 years = (y - 4) years.

  • Ravi's age before 4 years = (x - 4) years.

According to the above condition,

⟹ x - 4 = y - 4 + 8

Substitute the value of x from equation (1)

⟹ 3y - 4 = y + 4

⟹ 3y - y = 4 + 4

⟹ 2y = 8

⟹ y = 8/2

⟹ y = 4

Substitute the value of y in equation (1).

⟹ x = 3(4)

⟹ x = 12

Therefore,

  • Present age of Ravi = x = 12 years

  • Present age of Priya = y = 4 years.

Answered by Anonymous
44

Given

  • Four years ago ravi was 8 years older than priya.

We Find

  • Their present Ages

We know That

  • Ravi is 3 times older than priya.

So, X = 3y ( 1st Equation )

Ravi was 8 years older than priya , Four years ago.

So,

  • Priya ages before 4 years is ( y - 4 )

  • Ravi ages before 4 years is ( x - 4 )

According to the question

We substitute the value of x from equation

= 3y - 4 = y + 4

= 3y - y = 4 + 4

= 2y = 8

= y = 8/2

= y = 4

We substitute the value of y from equation

= x = 3(4)

= x = 12

So,

Present age of Ravi is 12 years

Present age of Ravi is 12 years Present age of Priya is 4 years

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