Question

Four years ago the age of a father was thrice of his son. After 9 years the age of the father will be
about twice that of his son. The present ages of the father and the son are:

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Answer 1

Answer:

Father's age 43

son ' s age 17

Step-by-step explanation:

let the age of son be x

let the age of father be y

Case 1 : Four years ago

x - 4 = ( y - 4 ) 3

x- 4 = 3y - 12

x - 3y + 8 = 0______(1)

Case 2 : after 9 years

x + 9 = ( y + 9 ) 2

x + 9 = 2y + 18

x - 2y - 9 = 0________(2)

from (1) n (2) we get

x - 3y + 8 = 0

x - 2y - 9 = 0

- +. +

_____________

0. - y + 17 = 0

y = 17

Now , put the value of y in eq (2)

x - 2y -9 = 0

x - 2 ( 17) - 9 = 0

x - 34 - 9 = 0

x - 43 = 0

x = 43

so father's age is 43 and son's age is 17

Hope the above answer will be helpfull for u ...

Thank you