Math, asked by mitalivaidya50, 7 months ago

Four years ago, the age of Ramesh was equal to the
sum of the present ages of his only son and
daughter. Five years ago, the ages of son and
daughter were in the ratio of 12 : 11. The present
age of their mother is twice the age of her daughter
three years ago and she is 12 years younger to
Ramesh. What is the present age of Ramesh?
(1) 56 years
(2) 62 years
134 60 years
(4) 52 years
(5) None of these​

Answers

Answered by sujatharaji82
3

Answer:

It is very hard I think none of these

Answered by apoorvajoshi270
0

Answer:

Answer is 60

Step-by-step explanation:

consider the age of son and daughter 5 years ago as 12k and 11k. Let the Father's age be f and mother's age be m.

four years ago father's age is = f-4

present age of son = 12k+5

present age of daughter = 11k+5

Now they have given

f-4=12k+5+11k+5

f-4=23k+10

f=23k+14-----(3)

mother is 12 years younger to father (Ramesh)

f=m+12 -------(1)

Also mother is twice the age of daughter 3 years ago

m=2(11k+5-3)

m=22k+4

substituting in (1)

f=22k+16 -----(2)

from (2) and (3)

22k+16 = 23k+14

k=2

f=60 years

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