Question

Four years ago, the father's age was three times the age of his son., the total of the ages of the father and the son after four years, will be 64 years. What is the father's age at present ?

Answer 1

Answer:42

Step-by-step explanation:

see let the son's age be x

therefore father's age will be = 3*x =3x

therefore according to statement,

after four years, the father's age will be = 3x+4     (4 is represented as per increasing on years)

and son's age will be x+4

therefore final equation will be,

3x+4+x+4 = 64

solving:

4x+8 = 64

4x = 64-8

4x = 56

x=56/4

x=14

therefore son's age is 14

and

father's age is 14*3 =

(answer) 42

Answer 2

$\huge\sf\pink{Answer}$

☞ Age of Father = 42 years

$\rule{110}1$

$\huge\sf\blue{Given}$

➝ Four years ago father's age is 3 times the age of his son

➝ Sum of both tue father and the son = 64 years

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

✭ Age of Father?

$\rule{110}1$

$\huge\sf\purple{Steps}$

$\star\sf\ Let \: the \: age \: of \: son \: be \: x \: years$

$\star\sf\ So, \: the \: age \: of \: father \: be \: 3x \: years$

$\underline{\bigstar\:\textbf{After \: 4 \: years \: from \: the \: present :}}$

$\normalsize\twoheadrightarrow\sf\ (Age \: of \: son) + (Age \: of \: father) = 64$

$\normalsize\twoheadrightarrow\sf\ (x + 4) + (3x + 4) = 64$

$\normalsize\twoheadrightarrow\sf\ x + 4 + 3x + 4= 64$

$\normalsize\twoheadrightarrow\sf\ 4x + 8 = 64$

$\normalsize\twoheadrightarrow\sf\ 4x = 56$

$\normalsize\twoheadrightarrow\sf\ x = \frac{\cancel{56}}{\cancel{4}}$

$\normalsize\twoheadrightarrow\sf\ x = 14$

$\normalsize\underline{\bullet{\purple{\sf\ {Age \: of \: son :}}}}$

$\normalsize\dashrightarrow\sf\ A_{s} = x \\ \\ \normalsize\red{\dashrightarrow\sf\ A_{s} = 14}$

$\normalsize\underline{\bullet{\green{\sf\ {Age \: of \: father :}}}}$

$\normalsize\dashrightarrow\sf\ A_{f} = 3x \\ \\ \normalsize\orange{\dashrightarrow\sf\ A_{s} = 3 \times\ 14 = 42yrs}$

$\rule{170}3$