Question

Four years ago the father's age was three times the age of his son the total of the ages of the father and son after 4 years will be 64 years what is the father's age at present

Answer 1

father's age=x
son's age=y

four yrs ago,
=> 3y=x
=> 3y-x=0 ____(1)

after 4 yrs,
=>x+3y+8=64 ________(2)
(4 yrs ago+4 yrs after=4+4=8yrs)

subtracting 1 from 2
=> x+3y+8=64
=>(-)-x+3y+0=0(signs changes)(3y-3y cancelled)
=> _________
2x+8=64
__________
=>2x+8=64
=>2x=64-8=56
=>x=56/2
=>x=28
PRESENT AGE OF FATHER=28

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