Four years ago the father was three times as old as the son. The sum of their present ages is 72 years. The present age of the father is ?
Answers
The present age of the father is 52 years.
Step-by-step explanation:
Solution :
Four years ago,
Let,
- Age of son = x
- Age of father = 3x
Present age of son = x + 4
Present age of father = 3x + 4
Also,
The sum of their present ages is 72 years
⇒ (x + 4) + (3x + 4) = 72
⇒ 4x + 4 + 4 = 72
⇒ 4x + 8 = 72
⇒ 4x = 72 - 8
⇒ 4x = 64
⇒ x = 64/4
⇒ x = 16
• Present age of son = x + 4
⇒ 16 + 4
⇒ 20
Present age of son = 20 years
• Present age of father = 3x + 4
⇒ 3 (16) + 4
⇒ 52
Present age of father = 52 years
★ The sum of their present ages is 72 years
⇒ 20 + 52 = 72
Therefore, the present age of the father is 52 years.
Answer:
- Present age of Father is 52 years.
Step-by-step explanation:
Given:
- Four years ago the father was three times as old as the son. The sum of their present ages is 72 years.
To Find:
- Present age of Father.
Solution:
Four years ago the father was three times as old as the son.
- Let, Son's age = x
- Father's age = 3x
Sum of their present ages is 72 years.
Present ages,
- Son's age= x + 4
- Father's age = 3x + 4
According to question,
➙(x + 4) + (3x + 4) = 72
➙x + 3x + 4 + 4 = 72
➙4x + 8 = 72
➙4x = 72 - 8
➙4x = 64
➙x = 64/4
➙x = 16 years
Hence,
Present age of son = x + 4
Present age of son = 16 + 4 = 20 years.
Present age of Father = 3x + 4
Present age of Father = 48 + 4 = 52 years.
Therefore,
- Present age of Father is 52 years.