Question

Fourier sine series of pie - x

Answer 1

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Find the Fourier sine series of f(x)=x on [0,L]. bn=2L∫L0xsinnπxLdx=−2nπ[xcosnπxL|L0−∫L0cosnπxLdx]=(−1)n+12Lnπ+2Ln2π2sinnπxL|L0=(−1)n+12Lnπ.

Refer this attachment

Answer 2

Answer:

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