Question

fourmula of tanc-tand

Answer 1

i) tan θ = sin θ/ cosθ

ii) sin(A-B)= sinAcosB-sinBcosA
Know we have find
tan C - tan D

=(sin C/cos C ) - (sinD/ cosD)

=(sinCcosD-sinDcosC)/(cosCcosD)
=sin(C-D)/(cosCcosD

Hope it helped