Question

fourth fifths of a number exceeds two thirds of the number by 10.​

Answer 1

Here is the answer for your question

Answer 2

Let the number required is x

(4/5) x-10 = (2/3) x

On rearranging, (4/5) x-(2/3) x = 10

Now taking the L.C.M of 3 and 5 is 15

(12x-10x)/15=10

On cross multiplication,

2x=150

x=150/2=75

So the required number is 75