Question

fourth term of a GP is 40 and tenth term is 2560. find the fifth term​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

let 1 st term is a

common ratio r

4th term =40=ar^(4-1)=ar^3

10 th term =2560=ar^(10-1)=ar^9

dividing,

ar^9/ar^3=2560/40

=> r^(9-3)=64

=> r^6=(2)^6

=> r=2

ar^3=40

=> a.2^3=40

=> a.8=40

=> a =40/8

=> a=5

so 1st term is 5 and common ratio is 2

so 5th term =ar^(5-1)=5.2^4=5.16=80