Question

\frac{(4 x \times 4) - (7 x - 8}{4x + 5} = - \frac{4}{3}
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Answer 1

Step-by-step explanation:

$\sf \dfrac{(4x \times 4)-(7x-8)}{4x+5} = - \dfrac{4}{3}$

$: \implies \sf \dfrac{16x-7x+8}{4x+5}=- \dfrac{4}{3}$

$:\implies \sf \dfrac{9x+8}{4x+5}=- \dfrac{4}{3}$

On cross-multiplying the terms ,

$:\implies \sf (9x+8)(3) = (-4) (4x+5)$

$: \implies \sf 27x + 24 = -16x - 20$

$:\implies \sf 27x+16x = -20-24$

$: \implies \sf 43x = - 44$

$:\implies \sf \pink{x=- \dfrac{44}{43}}\ \; \bigstar$

Answer 2

Answer:

your Q answer in the attachment

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