Question

\frac{4}{y} +\frac{4}{3y} =\frac{y}{3}[/

Answer 1

Answer:

$\frac{4}{y} + \frac{4}{3y} = \frac{y}{3}$

$\frac{12 + 4}{3y} = \frac{y}{3}$

$\frac{16}{3y} = \frac{y}{3}$

$48 = 3 {y}^{2}$

$y ^{2} = 16$

$y = \frac{ + }{ - } 4$

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