Question

Fraction of molecules (having energy greater or equal to activation energy) are plotted against kinetic
energy as shown
at temperature t
Energy of activate
Fraction of molecules
(t+10)at
Temperature B
E
D
Kinetic energy
с

Answer 1

ANSWER

In the given case:

E

a

=209.5kJ mol

−1

=209500J mol

−1

T=581K

R=8.314J K

−1

mol

−1

Now, the fraction of molecules of reactants having energy equal to or greater than activation energy is given as:

x=e

−Ea/RT

ln

x

=−E

a

/RT

logx=−

2.303RT

E

a

logx=−

2.303×8.314JK

−1

mol

−1

×581

209500Jmol

−1

=18.8323

Now, x= Anti log(18.8323)

=Antilog

19

ˉ

.1677Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy. Answer: Fraction of molecules having energy equal to greater than activation energy, Thus, = ? 18.8323 = x = antilog ( ) = 1.47 × 10?Fraction of molecules having energy equal to activation energy is 2.0 × 10-9.