Fraction of total volume occupied by atoms in a simple cube is
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2
Answer:
0.524 or 52.4% of total volume is occupied by atoms
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In the simple cube, no. of atoms/unit cell
= 8 × 1/8 = 1
Volume of the atom = 4/3 πr³
Volume of the cube = a³ = (2 r)³ = 8 r³ (∵ a = 2r)
Fractional occupied = 4/3 πr³ / 8r³
= π/6
Hope it helps you !!
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