Question

fraction-sixteen four by seven minus four one by twenty eight minus one one by fourteen​. write in process

Answer 1

Question:

$16 \dfrac{4}{7} - \: 4 \dfrac{1}{28} - 1 \dfrac{1}{14}$

Solution :

$16 \dfrac{4}{7} \: = \: \dfrac{(16 \times 7) + 4}{7} \: = \: \dfrac{(112 + 4)}{7} \: = \: \dfrac{116}{7} \\ \\ \\ 4 \dfrac{1}{28} \: = \: \dfrac{(4 \times 28) + 1}{28} \: = \: \dfrac{(112 + 1)}{28} \: = \: \dfrac{113}{28} \\ \\ \\ 1 \dfrac{1}{14} \: = \: \dfrac{(1 \times 14) + 1}{14} \: = \: \dfrac{(14 + 1)}{14} \: = \: \dfrac{15}{14}$

therefore,

$16 \dfrac{4}{7} - \: 4 \dfrac{1}{28} - 1 \dfrac{1}{14} \: = \: \dfrac{116}{7} \: - \: \dfrac{113}{28} \: - \: \dfrac{15}{14} \:$

taking LCM of , 7,14&28 which is 28

we get ,

$\dfrac{(116 \times 4) - (113 \times 1) - (15 \times 2)}{28} \\ \\ \\ = \dfrac{464 \: - \: 113 \: - \: 30}{28} \\\\ \\ = \dfrac{321}{28} \\ \\ = \: \dfrac{(319 + 2)}{28} \\ \\ \\ = \: \dfrac{(11 \times 28) + 2}{28} \\ \\ \\ = \: 11 \dfrac{2}{28}$

ANSWER :

$\dfrac{321}{28}  = 11 \dfrac{2}{28}$