Math, asked by rakbathsanga, 1 year ago

fractores
 {x}^{2}  - 2x - 3

Answers

Answered by ItzRadhika
2

Answer:

x²-2x-3

x²-(3-1)x-3

x²-3x+1x-3

(x²-3x)(1x-3)

x(x-3)1(x-3)

(x+1)(x-3)......

Answered by tejalpatel44510
1

x^2-2x-3

x^2 -3x+x-3

x(x-3) +1(x-3)

(x+1) (x-3)

x=-1 or x=3

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