Question

Fractorise a^3 - 1/a^3 - 2a + 2/a​

Answer 1

$\begin{gathered}{\Huge{\textsf{\textbf{\underline{\underline{\purple{Answer:}}}}}}}\end{gathered}$

$\implies$The answer is given below:

Now,

a³-1/a³ - 2a + 2/a

= (a - 1/a){a² + (ax 1/a) + 1/a²}-2(a - 1/a)

= (a - 1/a)(a² + 1/a² + 1) - 2(a - 1/a)

= (a - 1/a)(a² + 1/a² + 1-2)

= (a - 1/a)(a² + 1/a² - 1),

which is the required factorization.

• I Hope it's Helpful My Friend

Answer 2

Step-by-step explanation:

Now,

a³-1/a³ - 2a + 2/a

= (a - 1/a){a² + (ax 1/a) + 1/a²}-2(a - 1/a)

= (a - 1/a)(a² + 1/a² + 1) - 2(a - 1/a)

= (a - 1/a)(a² + 1/a² + 1-2)

= (a - 1/a)(a² + 1/a² - 1),

which is the required factorization.