Fractorize : 3+23y-8y²
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Answered by
47
3+23y-8y^2
=-8y^2+23y+3
=-8y^2+(24-1)y+3
=-8y^2+24y-y+3
=-8y(y-3)-1(y-3)
=(y-3)(-8y-1)
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=-8y^2+23y+3
=-8y^2+(24-1)y+3
=-8y^2+24y-y+3
=-8y(y-3)-1(y-3)
=(y-3)(-8y-1)
Plz mark me BRAINIEST if you like my answer
Answered by
4
hii
8y(squared)+23y-3
8y(squared)+24y-10y-3=0
8y(y+3) -1(y+3) =0
8y-1=0 y+3=0
hence y=1/8 , y=-3
#bmjssschoolaulakh#
8y(squared)+23y-3
8y(squared)+24y-10y-3=0
8y(y+3) -1(y+3) =0
8y-1=0 y+3=0
hence y=1/8 , y=-3
#bmjssschoolaulakh#
Anonymous:
plz mark it as brainiest ,...,
if you like my solution
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