Frame a polynomial whose zeros are 3-√3/5, 3+√3/5
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sorry I think it's difficult from me
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the zeros are-
alpha = 3-✓3/5
beta =3+✓3/5
product of zeroes:-
alpha×beta
(3-✓3+3+✓3)/5= 6/5
sum of zeros:-
alpha×beta
(3-✓3)/5×(3+✓3)/5 = 9-3/25=6/25
now,
x²-( alpha+beta)x+( alpha +beta )=0
x²/1-6/25+6/5×x=0
(25x²+30x-6)/25=0
25(25x²+30x-6)/25=0
25x²+30x-6=0
hence , it is the quadratic polynomial.
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