Question

frame a quadratic equation from roots 0 and-3​

Answer 1

Answer:

x^2+3x

Step-by-step explanation:

Let a=0 and b= -3

a+b = 0-3 = -3

a×b = 0×-3 = 0

Required equation = x^2-(a+b)x+ab

= x^2+3x+0 = x^2+3x

Answer 2

We know that the formation of quadratic equation if they have two roots $\bold{x_1}$ and $\bold{x_2}$ is

☞ x² + ( $\bold{x_1}$ + $\bold{x_2}$) x + $\bold{x_1}$ × $\bold{x_2}$ = 0

• Given roots —

• $\bold{x_1}$ = 0
• $\bold{x_2}$ = –3

Now ,

» Sum of the roots

= $\bold{x_1}$ + $\bold{x_2}$

= 0 + (-3)

= -3

» Product of the roots

= $\bold{x_1}$ × $\bold{x_2}$

= 0 × (-3)

= 0

∴ Required quadratic equation is —

• x² + ( $\bold{x_1}$ + $\bold{x_2}$) x + $\bold{x_1}$ × $\bold{x_2}$ = 0

→ x² + (-3)x + 0 = 0

→ x² - 3x = 0