Question

Frame a quadratic polynomial whose sum of zeroes is -2/3 and product of zeroes is -3.
Guys if u give with proper steps i will mark as brainliest.

Answer 1

Step-by-step explanation:

ATQ,

$\alpha + \beta = - 2\3$

and

$alpha x beta = - 3$

so , the formula to make quadratic equations is ( when two of its zeroes are given) is x^2 - sx + p

(s = sum of zeroes ) , ( p=product of zeroes )

• equation = x^2 - (-2/3)x + (-3)
• = x^2 + 2/3 x - 3
• = 3 ( x^2 + 2/3x -3)
• = 3x^2 + 2x - 6

HOPE IT HELPS YOU ...!!

Answer 2

Step-by-step explanation:

The formula for forming a quadratic polynomial is

QP = K ( x2 - Sx + P) = 0

Where S stands for sum of zeroes and P stands for product of zeroes

Now just put the values

QP = K ( x2 - ( -2/3x ) + ( -3) ) = 0

Take LCM

QP = K ( 3x2 + 2x - 9 / 3 ) = 0

Both K and the denominator 3 transfers to LHS and gets multiplied by 0 , so the answer that we get is

QP = ( 3x2 + 2x - 9 )